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x^2-450x+10000=0
a = 1; b = -450; c = +10000;
Δ = b2-4ac
Δ = -4502-4·1·10000
Δ = 162500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{162500}=\sqrt{2500*65}=\sqrt{2500}*\sqrt{65}=50\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-450)-50\sqrt{65}}{2*1}=\frac{450-50\sqrt{65}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-450)+50\sqrt{65}}{2*1}=\frac{450+50\sqrt{65}}{2} $
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